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5x^2+66x+168=0
a = 5; b = 66; c = +168;
Δ = b2-4ac
Δ = 662-4·5·168
Δ = 996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{996}=\sqrt{4*249}=\sqrt{4}*\sqrt{249}=2\sqrt{249}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-2\sqrt{249}}{2*5}=\frac{-66-2\sqrt{249}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+2\sqrt{249}}{2*5}=\frac{-66+2\sqrt{249}}{10} $
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